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Simplify : \(\frac{3^{-5n}}{9^{1-n}} \times 27^{n + 1}\)

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Question 6
A

33

B

35

C

3

D

32

Explanation

\(\frac{3^{-5n}}{9^{1-n}} \times 27^{n + 1}\)

 

\(\frac{3^{-5n}}{3^{2(1-n)}} \times 3^{3(n + 1)}\)

 

\(3^{-5n} \div 3^{2(1-n)} \times 3^{3(n + 1)}\)

 

 

\(3^{-5n - 2(1-n) + 3(n + 1)}\)

 

 

\(3^{-5n - 2 + 2n + 3n + 3}\)

 

\(3^{-5n + 5n + 3 - 2}\)

 

\(3^{1}\)

 

= 3


Correct option: C

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1 Comment(s)

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🙂 Philip Michael said on February 9, 2021 01:24pm
After solving this, i had 3^4n-1 using the law of indices
how come is the answer 3^2
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🙂 QUIZZERWEB replied on February 12, 2021 07:44pm
We are very sorry about that, the question has been updated
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