# The energy stored in a capacitor of capacitance 5F is 40J. Calculate the...

Question 307
A
4000V
B
200V
C
16V
D
6V
E
4V
##### Explanation

$$E = \frac{CV^{2}}{2}$$

$$V^{2} = \frac{2E}{C}$$

$$V^{2} = \frac{2\times 40}{5 \times 10^{-6}}$$

$$V^{2} = 16 \times 10^{6}$$

$$V = 4 \times 10^{3} = 4000v$$

Try this quiz in in E-test/CBT Mode
switch to

Question Map