# A converging lens of focal length 5cm forms a virtual image which is 10cm...

Question 354
A
2.0cm
B
3.3cm
C
5.0cm
D
10.0cm
E
15.0cm
##### Explanation

$$f = \frac{uv}{u+v}$$

$$5 = \frac{-10u}{-10+u}$$

$$50 + 5u = -10u$$

$$50 = -10u - 5u$$

$$u = \frac{50}{-15}$$

u= -3.3cm

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