A ball is projected horizontally from the top of a hill with a velocity...

Question 523
A
20m
B
40m
C
80m
D
160m
E
200m
Explanation
Initial horizontal velocity = 20ms-1

Initial vertical velocity = 0

s = ut + $$\frac{1}{2}gt^2$$ = 0 x 5 x 42

= 80m

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