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An electron charge 1.6 x 10-19C is accelerated in vacuum from rest at zero...

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Question 576
A
4.0 x 10-26J
B
4.0 x 10-21J
C
6.4 x 10-20J
D
3.2 x 10-15J
E
2.5 x 10-20J
Explanation
E = \(\frac{1}{2}QV = \frac{1}{2} \times 1.6 \times 10^{-19} \times 40000\)

= 3.2 x 10-15J

Correct option: D

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