# Calculate the resistance of the filament of lamp rated at 240V 60W

Question 621
A
240$$\Omega$$
B
360$$\Omega$$
C
960$$\Omega$$
D
144$$\Omega$$
E
2880$$\Omega$$
##### Explanation
P = $$\frac{V^2}{R} = \frac{240^2}{60} = 960$$

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