# The diagram below illustrates an a.c.source of 50V(r.m.s.), $$\frac{100}{\pi}$$Hz...

Question 626
A
1.33
B
1.25
C
0.80
D
0.75
E
0.60
##### Explanation
cos$$\theta = \frac{R}{Z}$$

R = $$\frac{V}{I} = \frac{40}{2} = 20$$

Z = R2 + $$^X_L$$ = 202 + 152 = 300

cos $$\theta = \frac{R}{Z} = \frac{20}{300} = 0.06$$

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