# The distance between two points in phase on a progressive wave is 5cm....

Question 905
A
4.00s
B
2.50s
C
0.25s
D
0.04s
##### Explanation
F = $$\frac{v}{\lambda} = \frac{0.2}{5 \times 10^{-2}} = 4Hz$$

T = $$\frac{1}{f} = \frac{1}{4} = 0.25s$$

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