Chemistry (2017) | Study Mode

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Question 31
Chemistry (2017) Q 31 image
A

fused CaO

B

H2O

C

NaOH

D

Concentrated H2SO4

Explanation
In the preparation of sulphur dioxide by the action of dilute acids on sulphates and bisulphites. conc H2SO4 helps to release SO2 from the mixture.
The setup represents the production of sulphur dioxide

Correct option: D
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Question 32
A
3-methybut-3-ene
B
2-methylbut-1-ene
C
2-ethylprop-1-ene
D
2-methylbut-2-ene
Explanation
CH2CH2 - CCH3CH2
Start the numbering from the terminal carbon.

Correct option: B
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Question 33
A
Fe3 + (H2O)6
B
FeO.H2O
C
Fe2O3.3H2O
D
Fe3O4.2H22O
Explanation
Iron [Fe] reacts with H2 in the presence of oxygen to form a rust.

4Fe + 3O2 ? 2 Fe2O2

Fe2O3 + H2O ? Fe2O3.H2O

Correct option: C
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Question 34
A
sp2 hybridized
B
sp3 hybridized
C
sp4 hybridized
D
sp hybridized
Explanation
Alkane's family are sp3 hybridized

Correct option: B
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Question 35
A

100c

B

273c

C

373c

D

0c

Explanation

Where -273c = 0K

i.e -273c + 273 = 0K

At zero kelvin, the volume of a gas becomes zero.


Correct option: B
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Question 36
A
20
B
32
C
14
D
12
Explanation
Molecular mass = vapour density X2

Mm of XO2 = x + 16(2) = x + 32

vapour density = 32

? x + 32 = 32 x 2

x + 32 = 64

x = 64 - 32

x = 32

? the relative molecular mass of X is 32
Relative molecular mass = vapour density x 2

Correct option: B
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Question 37
A
chlorine
B
sulphur (IV) oxide
C
carbon (IV) oxide
D
ammonia
Explanation
Upward delivery works well for hydrogen and ammonia, which are both less densed than air. Sometimes, they are collected over water.

Correct option: D
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Question 38
A
positive ion
B
neutral atom of a metal
C
neutral atom of a non-metal
D
negative ion
Explanation
protons = 9

neutrons = 10

electrons = 10

Electronic configuration = 2, 8

Ground state Electronic configuration=2, 7

It means that the atom has gained an electron thereby making it have a negative ion.

When an atom donates an electron, it becomes positively charged.

When an atom accepts an electron, it becomes negatively charged

Correct option: D
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Question 39
A
0.300g
B
0.250g
C
0.2242g
D
0.448g
Explanation
M = \(\frac{\text{Molar mass x Quantity of Electricity}}{\text{96500 x no of charge}}\)

= \(\frac{MmIT}{96500n}\)

Copper II Chloride = CuCl2

CuCl2 ? Cu2+ + 2Cl2

Mass of compound deposited = \(\frac{\text{Molar mass x Quantity of Electricity}}{\text{96500 x no of charge}}\)

Q = IT

I = 0.5A

T = 45 x 60

T = 2700s

Q = 0.5 x 2700

= 1350c

Molarmass = 64gmol-1

no of charge = + 2

Mass = \(\frac{64 \times 1350}{96500 \times 2}\)

Mass = 0.448g

Correct option: D
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Question 40
A

0.1

B

0.5

C

2

D

4

Explanation

The rate of dimension of a gas inversely proportional to the square root of its molecular mass or its density, which is Graham's Law of diffusion of gas.

R \(\frac{1}{\sqrt{Mm}}\) or R \(\frac{1}{\sqrt{D}}\)

Dx = 0.5gdm-3, Dy = 2gdm-3

R= \(\frac{K}{\sqrt{D}}\)

R\(\sqrt{D}\) = k

R1\(\sqrt{D_1}\) = R1\(\sqrt{D_2}\)

Rx\(\sqrt{D_x}\) = Ry\(\sqrt{D_y}\)

\(\frac{R_x}{R_y}\) = \(\frac{\sqrt{D_y}}{\sqrt{D_x}}\)

= \(\frac{\sqrt{2}}{\sqrt{0.5}}\)

= 2.0


Correct option: C

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