Mathematics 2011 | Study Mode

Join Discuss Share to WhatsApp
Question 21
A
-6
B
6
C
-12
D
12
Explanation
\(\begin{vmatrix} 2 & 3 \\ 5 & 3x \end{vmatrix}\) = \(\begin{vmatrix} 4 & 1 \\ 3 & 2x \end{vmatrix}\)

(2 x 3x) - (5 x 3) = (4 x 2x) - (3 x 1)

6x - 15 = 8x - 3

6x - 8x = 15 - 3

-2x = 12

x = \(\frac{12}{-2}\)

= -6

Correct option: A
Join Discuss Share to WhatsApp
Question 22
A
25
B
45
C
15
D
55
Explanation
\(\begin{vmatrix} 4 & 2 & -1 \\ 2 & 3 & -1 \\ -1 & 1 & 3 \end{vmatrix}\)

4 \(\begin{vmatrix} 3 & -1 \\ 1 & 3 \end{vmatrix}\) -2 \(\begin{vmatrix} 2 & -1 \\ -1 & 3\end{vmatrix}\) -1 \(\begin{vmatrix} 2 & 3 \\ -1 & 1 \end{vmatrix}\)

4[(3 x 3) - (-1 x 1)] -2 [(2x 3) - (-1 x -1)] -1 [(2 x 1) - (-1 x 3)]

= 4[9 + 1] -2 [6 - 1] -1 [2 + 3]

= 4(10) - 2(5) - 1(5)

= 40 - 10 - 5

= 25

Correct option: A
Join Discuss Share to WhatsApp
Question 23
A
\(\frac{1}{5}\) \(\begin{vmatrix} 2 & 1 \\ 3 & 4\end{vmatrix}\)
B
\(\frac{1}{5}\) \(\begin{vmatrix} 4 & -3 \\ -1 & 2\end{vmatrix}\)
C
\(\frac{1}{5}\) \(\begin{vmatrix} 2 & -1 \\ -3 & 4\end{vmatrix}\)
D
\(\frac{1}{5}\) \(\begin{vmatrix} 4 & 3 \\ 1 & 2\end{vmatrix}\)
Explanation
N = [2 3]

N-1 = \(\frac{adj N}{|N|}\)

adj N = \(\begin{vmatrix} 4 & -3 \\ -1 & 2 \end{vmatrix}\)

|N| = (2 x4) - (1 x 3)

= 8 - 3

=5

N-1 = \(\frac {1}{5}\) \(\begin{vmatrix} 4 & -3 \\ -1 & 2 \end{vmatrix}\)

Correct option: B
Join Discuss Share to WhatsApp
Question 24
A
120o
B
150o
C
30o
D
180o
Explanation
Interior angle = (n - 2)180

but, n = 12

= (12 -2)180

= 10 x 180

= 1800

let each interior angle = x

x = \(\frac{(n - 2)180}{n}\)

x = \(\frac{1800}{12}\)

= 150o

Correct option: B
Join Discuss Share to WhatsApp
Question 25
A
56cm2
B
49cm2
C
98cm2
D
28cm2
Explanation
Perimeter of circle = Perimeter of square

28cm = 4L

L = \(\frac{28}{4}\) = 7cm

Area of square = L2

= 72

= 49cm2

Correct option: B
Join Discuss Share to WhatsApp
Question 26
A
46 cm
B
36 cm
C
66 cm
D
26 cm
Explanation
From Pythagoras theorem

|OA|2 = |AN|2 + |ON|2

72 = |AN|2 + (5)2

49 = |AN|2 + 25

|AN|2 = 49 - 25 = 24

|AN| = \(\sqrt {24}\)

= \(\sqrt {4 \times 6}\)

= 26 cm

|AN| = |NB| (A line drawn from the centre of a circle to a chord, divides the chord into two equal parts)

|AN| + |NB| = |AB|

26 + 26 = |AB|

|AB| = 46 cm

Correct option: A
Join Discuss Share to WhatsApp
Question 27
A
48 cm3
B
33 cm3
C
60 cm3
D
27 cm3
Explanation
Volume of cube = L3

33 = 27cm3

volume of rectangular tank = L x B X h

= 3 x 4 x 5

= 60cm3

volume of H2O the tank can now hold

= volume of rectangular tank - volume of cube

= 60 - 27

= 33cm3

Correct option: B
Join Discuss Share to WhatsApp
Question 28
A
whose distance from X is always twice its distance from Y
B
whose distance from Y is always twice its distance from X.
C
which moves on the line XY
D
which is equidistant from the points X and y
Explanation

Explanation not provided, please join discuss, your contributions are welcomed


Correct option: D
Join Discuss Share to WhatsApp
Question 29
A
(2, 10)
B
(2, 8)
C
(2, 12)
D
(2, 6)
Explanation
P(x, y) Q(8, 6)

midpoint = (5, 8)

x + 8 = 5

\(\frac{y + 6}{2}\) = 8

x + 8 = 10

x = 10 - 8 = 2

y + 6 = 16

y + 16 - 6 = 10

therefore, P(2, 10)

Correct option: A
Join Discuss Share to WhatsApp
Question 30
A
5y - 2x -18 = 0
B
5y + 2x - 18 = 0
C
5y - 2x + 18 = 0
D
5y + 2x - 2 = 0
Explanation
2y = 5x + 4 (4, 2)

y = \(\frac{5x}{2}\) + 4 comparing with

y = mx + e

m = \(\frac{5}{2}\)

Since they are perpendicular

m1m2 = -1

m2 = \(\frac{-1}{m_1}\) = -1

\(\frac{5}{2}\) = -1 x \(\frac{2}{5}\)

The equator of the line is thus

y = mn + c (4, 2)

2 = -\(\frac{2}{5}\)(4) + c

\(\frac{2}{1}\) + \(\frac{8}{5}\) = c

c = \(\frac{18}{5}\)

\(\frac{10 + 5}{5}\) = c

y = -\(\frac{2}{5}\)x + \(\frac{18}{5}\)

5y = -2x + 18

or 5y + 2x - 18 = 0

Correct option: B

Try this quiz in in E-test/CBT Mode
switch to Mathematics 2011 in CBT Mode

Previous Page Next Page
Question Map
Quiz link
Share Mathematics 2011 with your audience
Share to WhatsApp CBT mode Study mode copy link
​​​Help keep QUIZZERWEB running! 
A donation makes a contribution towards the costs, the time and effort that's going on in building and improving this platform.