# Physics 2009 | Study Mode

Question 41
A
4.99 x 105 Nm-2
B
9.80 x 103 Nm-2
C
4.98 x 103 Nm-2
D
9.80 x 105 Nm-2
##### Explanation
PV = nRT
 P = nRT = 2 x 8.313 x 300 _V ___10-2

= 4.987 x 105 Nm-2

Question 42
A
reflection
B
deflection
C
diffraction
D
refraction
##### Explanation
Diffraction is spreading of wave after passing through a slit

Question 43
A
20 Nm-1
B
40 Nm-1
C
30 Nm-1
D
10 Nm-1
##### Explanation
F = Ke (Hooks law)
K = F/e = 80/4
= 20 Nm-1

Question 44
A
3.0 x 1014 Hz
B
6.0 x 1014 Hz
C
6.0 x 1012 Hz
D
2.5 x 1014 Hz
##### Explanation
f = c/
 f = c = 3 x 108 500 x 109

=6.0 x 1014 Hz

Question 45
A
12 V
B
8 V
C
2 V
D
36 V
##### Explanation
1/R = 1/R1 + 1/R2 = 1/3 + 1/6
= 3/6
R = 6/3 = 2
E = I(R + r) = 4(2 + 0) = 8v

Question 46
A
116.3 V
B
50.0 V
C
230.0 V
D
106.3 V
##### Explanation
V =
(v1 + v2)2 + VR2

V =
(40 + 110)2 + 802

V =
(-70)2 + 802

=
4900 + 6400

=
11300

= 106.3v

Question 47
A
$$\frac{-5}{4}$$
B
$$\frac{-5}{6}$$
C
o
D
5
##### Explanation

Question 48
A
2700
B
450
C
900
D
1800
E
No Correct Option
##### Explanation
Comparing y = 10Sin$$(1000\pi t - \frac{\pi x}{34} ) \\ \text{With } y = a \text{Sin }(net - kx)\\ K = \frac{\pi}{34}, \text{and phase difference}\\ J = KAC = \frac{\pi}{34} \times 1.53rad.\\ \text{But} \pi rad = 180^0 \\ \text{Therefore } \frac{1.53rad}{34} = \frac{1.53 \pi}{34} \times \frac{1}{\pi} \times 180^0 \\ =8.1^0$$

Question 49
A
0.200m
B
8.000m
C
0.125m
D
2.100m
E
No Correct Option
##### Explanation
The person's image distance v will be at the distance of 0.1m = 10cm for him to see objects at a distance of u.F = 5.0cm

$$\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \implies \frac{1}{10} + \frac{1}{u} = \frac{1}{5} \\ \frac{1}{u} = \frac{1}{5} - \frac{1}{10} = \frac{2-1}{10} = \frac{1}{10} \\ \text{therefore } u = 10cm = 0.1m$$

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