MATHEMATICS (2016) Study Mode

Try this quiz in CBT Mode
MATHEMATICS (2016) in CBT Mode

Please share this quiz link to your friends, they might need it!

Quiz link
Share MATHEMATICS (2016) with your friends
Share to WhatsApp Share Quiz CBT mode Study mode copy link
https://quizzerweb.com.ng/quiz?q=MATHEMATICS%2B%25282016%2529&id=26

Join Discuss Share Question Share to WhatsApp
Question 1 MATHEMATICS (2016) | JAMB/UTME (2016)
A
\(\frac{2x^3}{3}\) - 2x + k 
B
x3 + 2x + k 
C
\(\frac{2x^3}{3}\) + 2x + k 
D
x3 - 2x + k 
Explanation.
Share Answer \(\int\) \(\frac{2x^3 + 2x}{x}\) = \(\int\) \(\frac{2x^3}{x}\) + \(\frac{2x}{x}\) = \(\int\) (2x2 + 2) dx

\(\frac{2x^2+1}{2 + 1}\) + 2x + k

= \(\frac{2x^3}{3}\)+ 2x + k

Correct Option:
C
Join Discuss Share Question Share to WhatsApp
Question 3 MATHEMATICS (2016) | JAMB/UTME (2016)
A

2( \(\frac{1}{3}\)X + 6 )

 
B

\(\frac{2}{3}\) ( \(\frac{1}{3}\)X + 6)

 
C

\(\frac{2}{3}\) ( \(\frac{1}{3}\)X + 6)2

 
D

\(\frac{1}{3}\) ( \(\frac{1}{3}\)X + 6)2

 
Explanation.
Share Answer

Y = ( \(\frac{1}{3}\)X + 6)2

\(\frac{dy}{dx}\) = 2( \(\frac{1}{3}\)X + 6) \(\frac{1}{3}\)

= \(\frac{2}{3}\) ( \(\frac{1}{3}\)X + 6)


Correct Option:
B
Join Discuss Share Question Share to WhatsApp
Question 4 MATHEMATICS (2016) | JAMB/UTME (2016)
A
45 
B
10 
C
35 
D
30 
Explanation.
Share Answer 80 - x + x + 60 - x + 20 = 150
160 - x = 150
x = 160 - 150 = 10

Correct Option:
B
Join Discuss Share Question Share to WhatsApp
Question 5 MATHEMATICS (2016) | JAMB/UTME (2016)
A
B
\(\frac{3}{2}\) 
C
\(\frac{2}{3}\) 
D
Explanation.
Share Answer T2 = \(\frac{8}{9}\), T6 = 4\(\frac{1}{2}\)
ar = \(\frac{8}{9}\)
ar5 = \(\frac{9}{2}\)

\(\frac{ar}{ar^5}\) = \(\frac{8}{9}\) x \(\frac{2}{9}\)

\(\frac{1}{r^4}\) = \(\frac{16}{81}\)

r = \(\sqrt[4]{18/16}\) = \(\frac{3}{2}\)

Correct Option:
B
Join Discuss Share Question Share to WhatsApp
Question 7 MATHEMATICS (2016) | JAMB/UTME (2016)
A
B
C
D
Explanation.
Share Answer \(\frac{(n - 2) 180}{180}\) = \(\frac{1080}{180}\)

(n - 2) = 6
n = 6 + 2 = 8

Correct Option:
D
Join Discuss Share Question Share to WhatsApp
Question 8 MATHEMATICS (2016) | JAMB/UTME (2016)
A

82o

 
B

36o

 
C

72o

 
D

118o

 
Explanation.
Share Answer < MPT = 180o - 118o = 62o

< PML = 62o ( Alternative angle)

y + 2y + 10o + 62o = 180o (Angles on a straight line)

3y = 180 - 72
\(\frac{3y}{3}\) = \(\frac{108}{3}\)
y = 36o

< PMT = 2y + 10 = 2(36) + 10 = 82o

Correct Option:
A
Join Discuss Share Question Share to WhatsApp
Question 10 MATHEMATICS (2016) | JAMB/UTME (2016)
A

15

 
B

16

 
C

20

 
D

18

 
Explanation.
Share Answer

Number of students that plays only two games = 4 + 8 + 3  = 15


Correct Option:
A
Next Page
Question Map