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Question 2 Mathematics (2015) | JAMB/UTME (2015)
A

1 \( \frac{3}{8}\)

 
B

2 \( \frac{3}{4}\)

 
C

4 \( \frac{3}{8}\)

 
D

3 \( \frac{1}{5}\)

 
Explanation.
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1¼ ÷ [ 2 ÷ ¼] of 28

Apply BODMAS rules

\( \frac{5}{4}\) ÷ [ 2 ÷ ¼ \(\times\) 28 ]

\( \frac{5}{4} ÷ \frac{2}{7} \)


\( \frac{5}{4} \times \frac{7}{2} \)

\( \frac{35}{8}\)

= \(4 \frac{3}{8}\)


Correct Option:
C
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Question 3 Mathematics (2015) | JAMB/UTME (2015)
A

(x - 5) 2

 
B

(x + 5)(x + 4)

 
C

(x + 5)(x + 3)

 
D

(x + 3) 2

 
Explanation.
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\( x^2 + 9x + 20 \)

Find the two numbers whose product is 20 and its sum is 9}

\( 5x \times 4x = 20x^2\)


\(5x + 4x = 9x\)

\((x^2 + 5x) + (4x + 20)\)
\(

x(x + 5)+ 4(x + 5)

= (x + 5)(x + 4)\)


Correct Option:
B
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Question 4 Mathematics (2015) | JAMB/UTME (2015)
A

N36,000

 
B

N44,000

 
C

N40,000

 
D

N15,000

 
Explanation.
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No official Explanation yet!


Correct Option:
C
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Question 6 Mathematics (2015) | JAMB/UTME (2015)
A

(3, -9)

 
B

(-3, 9)

 
C

(-3, -9)

 
D

(-3, 0)

 
Explanation.
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Starting from 3x - z \(\leq\) 9

x = 0, substitute the value of x (i.e. x = 0) into the equation 3x - z \(\leq\) 9

3(0) - z \(\leq\) - 9

z \(\leq\) - 9

If z = 0

Then, 3x - 0 \(\leq\) 9

3x \(\leq\) 9

x \(\leq\) 3

Intercept of x and z i.e (x,z)

= (3, -9)


Correct Option:
A
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Question 7 Mathematics (2015) | JAMB/UTME (2015)
A

log104

 
B

log1040

 
C

log10-40

 
D

log104-

 
Explanation.
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log101.5 + 3 log102 - log100.3

log101.5 + log1023 - log100.3

[log10(1.5 \(\times\) 23) ÷ log100.3]

[log10(15/10 \(\times\) 8 ) ÷ log10( 3/10)]

log10(15/10 \(\times\) 8 \(\times\) 10/3 )

log1040


Correct Option:
B
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Question 8 Mathematics (2015) | JAMB/UTME (2015)
A

17.8cm2

 
B

15.8cm2

 
C

75.4cm2

 
D

54.7cm2

 
Explanation.
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The total surface area of a cylinder = 2πrl + 2πr2

= 2πr(l + r)

= 2 \(\times\) 3.14(7+%=5)

2 \(\times\) 3.14 \(\times\) 12

= 75.4cm (1DP)


Correct Option:
C
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Question 10 Mathematics (2015) | JAMB/UTME (2015)
A

15

 
B

20

 
C

30

 
D

25

 
Explanation.
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His annual salary = N2000

His allowances = N600

So his taxable income = Annual salary - allowance

= N2000 - N600

= N1400

He pay at 5%

Then, his allowance income tax 5/100 \(\times\) 600 = N30


Correct Option:
C
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