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Question 4 Mathematics (2018) | JAMB/UTME (2018)
A
\(\frac{5}{8}\) 
B
\(\frac{5}{16}\) 
C
\(\frac{1}{2}\) 
D
\(\frac{3}{8}\) 
Explanation.
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Each multiplication of elements gives 16 results out of which the ones that are not greater than 6 are asterisked (*) and they are 8 in numbers

  Pr(product of x and y NOT > 6 ) = \(\frac{8}{16}\) = \(\frac{1}{2}\)


Correct Option:
D
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Question 5 Mathematics (2018) | JAMB/UTME (2018)
A
1000 
B
2000 
C
3000 
D
4000 
Explanation.
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No official Explanation yet!


Correct Option:
B
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Question 7 Mathematics (2018) | JAMB/UTME (2018)
A
B
C
D
Explanation.
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Profit (P) = 10\(_x\) − \(_x\)2

  Maximum profit can be achieved when the differential of profit with respect to number of bags(x) is 0

  i.e. \(\frac{dp}{dx}\) = 0

 \(\frac{dp}{dx}\) = 10 - 2x = 0

  10 = 2x

  Then x = \(\frac{10}{2}\) = 5

  Answer is C


Correct Option:
C
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Question 8 Mathematics (2018) | JAMB/UTME (2018)
A
10° 
B
28° 
C
36° 
D
40° 
Explanation.
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The diagram shows angles at a point, the total angle at a point is 360

  x - 10 + 4x - 50 + 2x + 3x + 20 = 360

  10x - 40 = 360

  10x = 360 + 40

  10x = 400

  x = \(\frac{400}{10}\)

  x = 40


Correct Option:
D
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Question 9 Mathematics (2018) | JAMB/UTME (2018)
A
\(\frac{9}{13}\) 
B
\(\frac{7}{13}\) 
C
D
9\(\frac{3}{5}\) 
Explanation.
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\(\frac{3}{4}\) t + \(\frac{1}{3}\) (21 - t) = 11

  Multiply through by the LCM of 4 and 3 which is 12

  12 x(\(\frac{3}{4}\) t) + 12 x (\(\frac{1}{3}\) (21 - t)) = (11 x 12)

  9t + 4(21 - t) = 132

  9t + 84 - 4t = 132

  5t + 84 = 132

  5t = 132 - 84 = 48

  t = \(\frac{48}{5}\)

  t = 9 \(\frac{3}{5}\)

  Answer is D


Correct Option:
D
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Question 10 Mathematics (2018) | JAMB/UTME (2018)
A
\(\frac{5}{6}\) 
B
\(\frac{7}{12}\) 
C
\(\frac{5}{12}\) 
D
\(\frac{1}{6}\) 
Explanation.
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No official Explanation yet!


Correct Option:
C
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