Mathematics 2012 Study Mode

Try this quiz in CBT Mode
Mathematics 2012 in CBT Mode

Please share this quiz link to your friends, they might need it!

Quiz link
Share Mathematics 2012 with your friends
Share to WhatsApp Share Quiz CBT mode Study mode copy link
https://quizzerweb.com.ng/quiz?q=Mathematics%2B2012&id=208

Join Discuss Share Question Share to WhatsApp
Question 21 Mathematics 2012 | JAMB/UTME (2012)
A
B
C
D
Explanation.
Share Answer \(\begin{vmatrix} 5 & 3 \\ x & 2 \end{vmatrix}\) = \(\begin{vmatrix} 3 & 5 \\ 4 & 5 \end{vmatrix}\)

10 - 3x = 15 - 20

-3x = 15 - 20 - 10

-3x = -15

x = 5

Correct Option:
C
Join Discuss Share Question Share to WhatsApp
Question 22 Mathematics 2012 | JAMB/UTME (2012)
A
-1 
B
C
D
Explanation.
Share Answer Recall that a unit matrice is a diagonal matrix in which the elements in the leading diagonal is unity. Therefore,

I3 = \(\begin{pmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{pmatrix}\)

I3 = \(+1\begin{vmatrix} 1 & 0 \\ 0 & 1 \end{vmatrix} - 0\begin{vmatrix} 0 & 0 \\ 0 & 1 \end{vmatrix} + 0 \begin{vmatrix} 0 & 1 \\ 0 & 0 \end{vmatrix} \)

I3 = +1(1 - 0) - 0(0 - 0) + 0(0 - 0)

= 1(1)

= 1

Correct Option:
C
Join Discuss Share Question Share to WhatsApp
Question 24 Mathematics 2012 | JAMB/UTME (2012)
A
3.92cm3 
B
2.13cm3 
C
1.97cm3 
D
1.62cm3 
Explanation.
Share Answer Volume of cuboid = L x b x h

= 0.76cm x 2.6cm x 0.82cm

= 1.62cm3

Correct Option:
D
Join Discuss Share Question Share to WhatsApp
Question 25 Mathematics 2012 | JAMB/UTME (2012)
A
line parallel to 7x + 13y + 8 = 0 
B
circle 
C
semicircle 
D
bisector of the line 7x + 13y + 8 = 0 
Explanation.
Share Answer

No official Explanation yet!


Correct Option:
A
Join Discuss Share Question Share to WhatsApp
Question 26 Mathematics 2012 | JAMB/UTME (2012)
A
\(\frac{1}{2}\) 
B
\(\frac{2}{5}\) 
C
\(-\frac{4}{7}\) 
D
\(-\frac{2}{3}\) 
Explanation.
Share Answer PQ = \(\frac{y_1 - y_0}{x_1 - x_0}\) = \(\frac{-3 - (-7)}{-2 - 5}\) = \(\frac{-3 + 7}{-2 - 5}\) = \(\frac{4}{-7}\)

Correct Option:
C
Join Discuss Share Question Share to WhatsApp
Question 27 Mathematics 2012 | JAMB/UTME (2012)
A
\(\sqrt{13}\) 
B
\(3\sqrt{2}\) 
C
\(\sqrt{26}\) 
D
\(10\sqrt{5}\) 
Explanation.
Share Answer P1 (4, 3), P2 (x, y)

y = 2x + 4 .....(1)

y = 7 - x .....(2)

Substitute (2) in (1)

7 - x = 2x + 4

7 - 4 = 2x + x

3 = 3x

x = 1

Substitute in eqn (2)

y = 7 - x

y = 7 - 1

y = 6

P2 (1, 6)

Distance between 2 points is given as

D = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)

D = \(\sqrt{(1 - 4)^2 + (6 - 3)^2}\)

D = \(\sqrt{(-3)^2 + (3)^2}\)

D = \(\sqrt{9 + 9}\)

D = \(\sqrt{18}\)

D = \(\sqrt{9 \times 2}\)

D = \(3\sqrt{2}\)

Correct Option:
B
Join Discuss Share Question Share to WhatsApp
Question 28 Mathematics 2012 | JAMB/UTME (2012)
A
y = 2x - 3 
B
y = 2x + 5 
C
y = 3x - 2 
D
y = 2x + 1 
Explanation.
Share Answer \(\frac{y - y_1}{x + x_1}\) = \(\frac{y_2 - y_1}{x - x_1}\)

\(\frac{y - 1}{x + 2}\) = \(\frac{4 - 1}{-\frac{1}{2} + 2}\)

= \(\frac{y - 1}{x + 2}\) = \(\frac{3}{\frac{3}{2}}\)

y = 2x + 5

Correct Option:
B
Join Discuss Share Question Share to WhatsApp
Question 29 Mathematics 2012 | JAMB/UTME (2012)
A
\(\frac{1}{2}\) 
B
\(\frac{\sqrt{2}}{2}\) 
C
\(-\frac{\sqrt{2}}{2}\) 
D
\(-\frac{1}{2}\) 
Explanation.
Share Answer

\(\theta\) = 135o

Cos 135o = Cos(90 + 45)o

= cos90ocos45o - sin90osin45o

= 0cos45o - (1 x \(\frac{\sqrt{2}}{2}\))

= \(-\frac{\sqrt{2}}{2}\)


Correct Option:
C
Join Discuss Share Question Share to WhatsApp
Question 30 Mathematics 2012 | JAMB/UTME (2012)
A
2x - \(\frac{1}{x^2}\) 
B
2x + x2 
C
2x - x2 
D
2x + \(\frac{1}{x^2}\) 
Explanation.
Share Answer y = x2 - \(\frac{1}{x}\)

y = x2 - x-1

\(\frac{\delta y}{\delta x}\) = 2x + x-2


\(\frac{\delta y}{\delta x}\) = 2x + \(\frac{1}{x^2}\)

Correct Option:
D
Previous Page Next Page
Question Map