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Question 2 Mathematics 2014 | JAMB/UTME (2014)
A
N53,000 
B
N52,000 
C
N51,000 
D
N50,000 
Explanation.
Share Answer SP = Nx
CP = N60,000
Percentage loss = 15%
Using percentage loss...

\(\frac{CP - SP}{CP} = \text{100%}\)

\(\text{15%} = \frac{60000 - x}{60000} \times \text{100%}\)

\(\text{15%} \times 60000 = (60000 - x)\text{100%}\)

\(60000 - x = \frac{\text{15%} \times 60000}{\text{100%}}\)

60000 - x = 3 x 3000

60000 -x = 9000

x = 60000 - 9000

x = N51,000

Correct Option:
C
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Question 3 Mathematics 2014 | JAMB/UTME (2014)
A
8.6 x 10-3 
B
8.3 x 10-2 
C
8.6 x 10-1 
D
8.6 x 10 
Explanation.
Share Answer 0.00043 x 2000

= 43 x 10-5 x 2 x 103

= 43 x 2 x 10-5+3

= 86 x 10-2

= 8.6 x 101 x 10-2

= 8.6 x 10-1

Correct Option:
C
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Question 4 Mathematics 2014 | JAMB/UTME (2014)
A
N40,500 
B
N45,000 
C
N52,500 
D
N62,000 
Explanation.
Share Answer Let;
M = Man monthly net earnings

Then;

\(\text{N4500} = \frac{\text{10%}}{\text{100%}} \times M \)

\(M = \frac{\text{N4500} \times \text{100%}}{\text{10%}} \)

M = N45,000

Correct Option:
B
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Question 5 Mathematics 2014 | JAMB/UTME (2014)
A
6.6252 
B
6.6253 
C
66.252 
D
66.253 
Explanation.
Share Answer If log 7.5 = 0.8751
Then 2log75 + log750
= 2(1.8751) + 2.8751
= 3.7502 + 2.8751
= 6.6253

Correct Option:
B
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Question 7 Mathematics 2014 | JAMB/UTME (2014)
A
3\(\sqrt{6} - 7\) 
B
3\(\sqrt{6} - 7\) 
C
3\(\sqrt{6} - 1\) 
D
3\(\sqrt{6} + 1\) 
Explanation.
Share Answer \(= \frac{2\sqrt{2} - \sqrt{3}}{\sqrt{2} + \sqrt{3}} \times \frac{\sqrt{2} - \sqrt{3}}{\sqrt{2} + \sqrt{3}}\)

\(= \frac{2\sqrt{2}(\sqrt{2}) + (2\sqrt{2})(-\sqrt{3})-\sqrt{3}(\sqrt{2})-\sqrt{3}(-\sqrt{3})}{(\sqrt{2})^2-(\sqrt{3})^2}\)

\(= \frac{2 \times 2 - 2\sqrt{6} - \sqrt{6} + 3}{2 - 3}\)

\(= \frac{4 - 3\sqrt{6} + 3}{-1}\)

\(= \frac{7 - 3\sqrt{6}}{-1}\)

\(= \frac{7}{-1} - \frac{3\sqrt{6}}{-1}\)

\(= -7 + 3\sqrt{6}\)

\(= 3\sqrt{6}-7\)

Correct Option:
A
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Question 10 Mathematics 2014 | JAMB/UTME (2014)
A
\(\frac{k + w}{t^2}\) 
B
\(\frac{k - w}{t^2}\) 
C
\(\frac{k + w}{t}\) 
D
\(\frac{k - w}{t}\) 
Explanation.
Share Answer gt2 - k - w = 0

gt2 = k + w

\(g = \frac{k + w}{t^2}\)

Correct Option:
A
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