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Question 61
A
0.33 
B
0.50 
C
0.67 
D
0.90 
Explanation.
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Volume of liquid displaced

 = \(\frac{2}{3}\)(0.5)\(^3\)

  Mass of liquid displaced = mass of floating cube = 75kg

  Density of liquid = \(\frac{mass}{volume}\)

  = \(\frac{75}{(\frac{7}{3(0.5)})}\)  × 3

  = 0.9 × 103kgm\(^{-3}\)

  R.D of liquid = \(\frac{(0.9 )}{(1.0)}\) × 103

  = 0.9


Correct Option:
D

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Question 62
A
330.0m 
B
335.4m 
C
660.0m 
D
670.8m 
Explanation.
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Recall V = F × lambda
= 260 × 1.29
= 335.4ms\(^{-1}\)


Correct Option:
B

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Question 63
A
Low density 
B
Hypothermal conductivity 
C
Low electrical resistivity 
D
Low melting point 
Explanation.
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Fuse wires have a low melting point so that if a huge amount of current is passed through it to any appliance than that wire would melt and stop the appliance from getting damaged by not letting the current pass any further.


Correct Option:
D

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Question 64
A
60V 
B
150V 
C
225V 
D
360V 
Explanation.
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P = 40W

  R = 90W

  V = ?

  P = \(\frac{V^2}{R}\)

  V\(^2\) = PR = 40 x 90

  V\(^2\) = 3000

  V = √3600

  V = 60N


Correct Option:
A

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Question 65
A
Mercury is a metal 
B
The cohesive force between its molecules is greater than the adhesive force between mercury and glass molecules 
C
The cohesive force between its molecules is less than the adhesive force between mercury and glass molecules 
D
The viscosity of mercury is height 
Explanation.
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In case of small drops of mercury, the gravitational potential energy is negligible in comparison to the potential energy due to surface tension.Consequently, to keep the drop in equilibrium, the mercury drop’s surface tends to contract so that its surface area will be the least for a sphere and the drops will be spherical.

  But in the case of bigger drops of mercury, the potential energy due to gravity is predominant over the potential energy due to surface tension.Consequently, to keep equilibrium , the mercury drop tends to assume minimum potential energy as possible, the drop becomes oval in shape and lower center of gravity.


Correct Option:
B

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Question 66
A
33\(^o\)c 
B
40\(^o\)c 
C
25\(^o\)c 
D
10\(^o\)c 
Explanation.
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Water 1 => M = 150g = 0.15kg,

  θ\(_2\) = 60\(^o\)C; θ\(_1\) = θ

  Q\(_1\) = MC (θ\(_2\) – θ\(_1\))

  = 0.15C (60 - θ)

  Water 2 => M = 300g = 0.3kg

  θ1 = 20\(^o\)C, θ\(_2\) = θ

  Q2 = MC (θ\(_2\) – θ\(_1\))

  = 0.3C (θ – 20)

  Combining Q1 and Q2

  0.15C (60 - θ) = 0.3C (θ – 20)

  9 – 0.15θ = 0.3θ – 6

  0.3θ + 0.15θ = 9 + 6

  0.45 θ = 15

  θ = 33.33\(^o\)C


Correct Option:
A

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Question 67
A
Transitional Motion 
B
Rotational Motion 
C
Brownian Motion 
D
Oscillatory Motion 
Explanation.
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Brownian motion, also called Brownian movement, any of various physical phenomena in which some quantity is constantly undergoing small, random fluctuations.
If a number of particles subject to Brownian motion are present in a given medium and there is no preferred direction for the random oscillations, then over a period of time the particles will tend to be spread evenly throughout the medium.


Correct Option:
C

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Question 68
A
thermionic emission 
B
nuclear fission 
C
thermonuclear fusion 
D
photoelectric emission 
Explanation.
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Thermionic emission: thermally induced flow of charge
Nuclear fission: nuclear reaction or a radioactive decay process
Photoelectric emission: emission of electrons or other free carriers when light shines on a material


Correct Option:
C

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Question 69
A
X – ray 
B
Y –ray 
C
α – particles 
D
neutron 
Explanation.
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Y – Ray is a penetrating electro-magnetic radiation.
α – particle is produced in the process of alpha decay.
Neutron is a sub-atomic particle.


Correct Option:
A

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Question 70
A
Convection 
B
Radiation 
C
Conduction 
D
Reflection 
Explanation.
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Radiation refers to the transmission of energy as electromagnetic radiation from its emission at a heated surface to its absorption on another surface, a process requiring no medium to convey the energy.
Conduction is the transferring of heat by direct contact.
Convection is transferring heat through the motions of fluids (gases and liquids).


Correct Option:
B

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