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Question 81 Physics (2018) | JAMB/UTME (2018)
A
Pair of calipers 
B
Meter rule 
C
Micrometer screw gauge 
D
Tape rule 
Explanation.
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No official Explanation yet!


Correct Option:
C
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Question 82 Physics (2018) | JAMB/UTME (2018)
A
Heat dissipation 
B
Production of eddy currents 
C
Excessive current discharge 
D
Excessive voltage discharge 
Explanation.
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The primary reason that power is transmitted at high voltages is to increase efficiency. As electricity is transmitted over long distances, there are inherent energy losses along the way. High voltage transmission minimizes the amount of power lost as electricity flows from one location to the next. How? The higher the voltage, the lower the current. The lower the current, the lower the resistance losses in the conductors. And when resistance losses are low, energy losses are low also. Electrical engineers consider factors such as the power being transmitted and the distance required for transmission when determining the optimal transmission voltage


Correct Option:
A
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Question 83 Physics (2018) | JAMB/UTME (2018)
A

17cm

 
B

20cm

 
C

25cm

 
D

100cm

 
Explanation.
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F = \(\frac{uv}{u + v}\)

20 = \(\frac{100 \times v}{100 + v}\)

v = 25cm


Correct Option:
C
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Question 84 Physics (2018) | JAMB/UTME (2018)
A
3.75cm 
B
6.70cm 
C
10.00cm 
D
15.00cm 
Explanation.
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V = 6cm

  M = 6cm

  Recall m = U = \(\frac{V}{U}\)

  U = \(frac{V}{M}\)

  =U = \(\frac{6}{0.6}\)

  U = 10

  \(\frac{1}{U}\) + \(\frac{1}{V}\) = \(\frac{1}{F}\)

  \(\frac{1}{10}\) + \(\frac{1}{6}\)

= \(\frac{1}{F}\)

  6 + \(\frac{10}{60}\)

\(\frac{16}{60}\) = \(\frac{1}{F}\)

  F = \(\frac{60}{16}\)

=  3.75cm


Correct Option:
A
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Question 85 Physics (2018) | JAMB/UTME (2018)
A
10cm 
B
20cm 
C
30cm 
D
40cm 
Explanation.
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F= 15cm

  M = 3

  M = \(\frac{v}{u}\)

  V =3u

  \(\frac{1}{f}\) = \(\frac{1}{u}\) + \(\frac{1}{v}\)

  \(\frac{1}{15}\) = \(\frac{1}{u}\) - \(\frac{1}{3u}\)

  \(\frac{1}{15}\) =   \(\frac{2}{3u}\)

U =10cm

  D = u + v

  = 10 +30 = 40cm


Correct Option:
D
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Question 86 Physics (2018) | JAMB/UTME (2018)
A
Voltaic cell 
B
Emission of electron by incident radiation 
C
Emission of protons by incident radiation 
D
Photographic plate 
Explanation.
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No official Explanation yet!


Correct Option:
B
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Question 87 Physics (2018) | JAMB/UTME (2018)
A
1.10 Ω 
B
1.64 Ω 
C
2.44 Ω 
D
27.50 Ω 
Explanation.
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\(\frac{V_1}{V_2}\) = \(\frac{L_1}{(V_2 − L_1)}\)

 \(\frac{R_1}{R_2}\) = \(\frac{ L_1}{(V_2 − L_1)}\)

  \(\frac{2}{R_2}\) = \(\frac{55}{45}\)

  R\(_2\) = 2 × \(\frac{45}{55}\)
= 1.64Ω


Correct Option:
B
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Question 88 Physics (2018) | JAMB/UTME (2018)
A
3,600J 
B
6,000J 
C
7,200J 
D
14,400J 
Explanation.
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Power drawn by the resistor = IV = (2)(3) = 24W = 24J/s

  Energy dissipated = power × time = (24)(5)(60) = 7200J


Correct Option:
C
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Question 89 Physics (2018) | JAMB/UTME (2018)
A

0.33

 
B

0.50

 
C

1.50

 
D

3.00

 
Explanation.
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R.d = \(\frac{\text{weight in air}}{\text{apparent loss of weight in water}} = \frac{45}{45 - 15}\) = \(\frac{45}{30} = 1.50\)


Correct Option:
C
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Question 90 Physics (2018) | JAMB/UTME (2018)
A
66m 
B
136m 
C
264m 
D
528m 
Explanation.
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Distance = speed × time
= (3400) × (0.812)
= 136m


Correct Option:
B
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