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Question 21
A
10 cm in front of the mirror. 
B
5 cm in front of the mirror 
C
10 cm behind the mirror 
D
5 cm behind the mirror 
Explanation.
Share Answer u = 5 cm , f = 10 cm, v = ?
(1)/v + (1)/u = (1)/f
(1)/v + (1)/5 = (1)/10
= (1)/v = (1)/10 = (1)/5 = (1 - 2)/10 = (1)/10
v = - 10 cm
The image is 10 cm behind the mirror

Correct Option:
C

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Question 22
A
4. 0 cm 
B
3. 0 cm 
C
12.0 cm 
D
9.0 cm 
Explanation.
Share Answer f = -12 cm, v = - 6 cm
(1)/v + (1)/u =(1)/f
(1)/-6 + (1)/u = (1)/-12
(1)/u = (1)/-12 + (1)/6 = (1 + 2)/12 = (1)/12
u = 12 cm

Correct Option:
C


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Question 24
A
x is same as in y 
B
x and y is same as in vacuum 
C
x is higher than in y 
D
y is higher than in x 
Explanation.
Share Answer Since 1.51, the refractive index of X is greater than 1.33, the refractive index of y, the speed of light in y is higher than that in X

Correct Option:
D

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Question 25
A
interference 
B
diffraction 
C
accomodation 
D
superposition 
Explanation.
Share Answer The leaves collapse as the position charges on the rod neutralize the negative charges on the electroscope

Correct Option:
C


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Question 27
A
close up 
B
become positively charged 
C
become negatively charged 
D
open further 
Explanation.
Share Answer The leaves collapse as the positive charges on the rod neutralize the negative charges on the electroscope.

Correct Option:
A

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Question 28
A
3.86 x 105
B
3.56 x 105
C
1.80 x 104
D
2.16 x 105
Explanation.
Share Answer Energy generated = power X time = 60w x 1h = 60 x 60 x 60 ws = 216000j = 2.16 x 105J

Correct Option:
D

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Question 29
A
5.60 v 
B
24.00 v 
C
0.24 v 
D
2.40 v 
Explanation.
Share Answer Number of tunes, n = 500
Area, A = 0.2m + 0.2m = 0.4m2
change of flux density A B
= 1.0 - 0.4 = 0.6T
Tune, t = 5 su
Induced emf, = (AB AN)/AT
(0.6 x 0. 04 x 500)/5
= 2.4v

Correct Option:
D


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