Physics 2010 | Study Mode

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Question 21
A
retina 
B
iris 
C
cornea 
D
pupil 
Explanation.
Share Answer The retina is light sensitive layer living the inner wall of the eye where image is formed. in the camera, image is formed on a light sensitive film.

Correct Option:
A
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Question 22
A
2 cm 
B
3 cm 
C
4 cm 
D
5 cm 
Explanation.
Share Answer (1)/v + (1)/u = (1)/f
(1)/v + (1)/15 = (1)/5
(1)/v = (1)/5 - (1)/15 = (3 - 1)/15 = (2)/15
v = (15)/2 = 7.5 cm
magnification = (v)/u = (image size)/object size
(7.5)/15 = (X)/4
image size. X = (7.5 x 4)/15 = 2 cm

Correct Option:
A
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Question 23
A
2.50 cm 
B
6.67 cm 
C
7.50 cm 
D
7.63 cm 
Explanation.
Share Answer Refraction index, n = (real depth)/apparent depth
1.5 = (10)/X
X = (10)/1.5 = 6.67 cm

Correct Option:
B
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Question 24
A
convex lens 
B
concave lens 
C
convex mirror 
D
concave mirror 
Explanation.
Share Answer Concave lens diverges parallel rays of light. A short sighted person has the image formed before the retina,and the rays have to be diverged so that they intersect to form image onto the retina

Correct Option:
B
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Question 25
A
different hidden colours in the glass 
B
different speeds of the colour in the glass 
C
defects in the glass 
D
high density of the glass 
Explanation.
Share Answer Dispersion is the splitting of white light into its spectral component colours and is caused by different speed of the colours in the prisma

Correct Option:
B
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Question 26
A
be induced 
B
converge 
C
diverge 
D
remain constant 
Explanation.
Share Answer Since the charged rod is not in contact with the electroscope, the leaves divergence will be induced

Correct Option:
C
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Question 27
A
make pass through the trasformers 
B
increase the power supply 
C
make it travel fast 
D
prevent overheating of the coil 
Explanation.
Share Answer H eat generated in a wire carrying current, H = 12 Rt.
so, when voltage is high and current is low heat generated in the wire will be minimal.
Therefore, high voltage and low current prevent overheating of the coil.

Correct Option:
D
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Question 28
A
B
C
D
10 
Explanation.
Share Answer R = (Vg)/lg = G, where lg = current through galvanometer
R = resistance of the multiplier
G = resistance of the galvanometer
G = (vg-R)/lg 5(1000/10) - 490 = 500 -490 = 10

Correct Option:
D
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Question 29
A
500.0J 
B
250.0J 
C
62.5J 
D
50.0J 
E
no correct option 
Explanation.
Share Answer Total inductance,L = L1 + L2 = m
15 + 5 = 20mH = (20)H/1000
1 = 5A
Energy of inductor, (1)/2 L I2
= (1)/2 X (20)/1000 X 5-2
= 0.25 J

Correct Option:
E
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