Mathematics | Study Mode

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Question 2
A
x \(\alpha\) z 
B
x \(\alpha\) \(\frac{1}{z}\) 
C
a \(\alpha\) z\(^2\) 
D
x \(\alpha\) \(\frac{1}{z^2}\) 
Explanation.
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\(x \propto \frac{1}{y}\), y \(\propto\) z

x = \(\frac{k}{y}\)

y = mz

Since y = mz,

x = \(\frac{k}{mz}\), where k and m are constants. Hence,

x \(\propto\) \(\frac{1}{z}\)


Correct Option:
B
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Question 3
A
\(\frac{14}{15}\) 
B
\(\frac{13}{15}\) 
C
\(\frac{4}{5}\) 
D
\(\frac{11}{15}\) 
Explanation.
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\(\frac{3\frac{1}{4} \times 1\frac{3}{5}}{11\frac{1}{3} - 5 \frac{1}{3}}\) = \(\frac{\frac{26}{5}}{\frac{18}{3}}\) = \(\frac{26}{5} \div \frac{18}{3}\)

= \(\frac{13}{15}\)


Correct Option:
B
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Question 4
A
1 : 4 
B
1 : 5 
C
2 : 5 
D
5 : 2 
Explanation.
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Tunde: Ola \(\to\) 1 : 2 ; Ola; Musa \(\to\) 4 : 5

\(\frac{1}{2}\) x \(\frac{4}{5}\)

= \(\frac{2}{5}\)


Correct Option:
C
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Question 5
A
iii only 
B
i and ii 
C
ii and iii only 
D
i, ii and iii 
Explanation.
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M = {3, 4, 5, 6, 7,}, N = {9, 10, 11, 12}


Correct Option:
A
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Question 6
A
a + b + 1 
B
ab - 1 
C
a - b + 1 
D
b - a + 1 
Explanation.
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\(\frac{\log 7 \times \log 10}{\log 2}\)

log 7 x log 10 \(\div\) log 2

a + 1 - b

a - b + 1


Correct Option:
C
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Question 7
A
B
C
D
Explanation.
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x = \(\frac{2}{3}\) and y = - 6

xy - \(\frac{y}{x}\)

\(\frac{2}{3} - (6)^2 - (-6) \div \frac{2}{3}\)

= -4 - (6) x \(\frac{3}{2}\)

= -4 - (-6) x \(\frac{3}{2}\)

= -4 - (-9)

= -4 + 9

= 5


Correct Option:
B
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Question 8
A
\(\frac{1}{5}\) 
B
\(\frac{2}{5}\) 
C
\(\frac{3}{5}\) 
D
\(\frac{4}{5}\) 
Explanation.
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\(\frac{1}{5x} + \frac{1}{x}\)= 3

\(\frac{1 + 5}{5x}\) = 3

6 = 15x

x = \(\frac{6}{15}\)

= \(\frac{2}{5}\)


Correct Option:
B
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Question 9
A
N1,820.00 
B
2,000.00 
C
N2,020.00 
D
N2,040.00 
Explanation.
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Let a girl's share = x + 20

4x + 5(x + 20) = 18,100

4x + 5x + 100 = 18,100

9x + 100 = 18,100

9x = 18,000

x = \(\frac{18,000}{9}\)

x = 2,000


Correct Option:
B
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