MATHEMATICS (2016) | Study Mode

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Question 1
A
\(\frac{2x^3}{3}\) - 2x + k 
B
x3 + 2x + k 
C
\(\frac{2x^3}{3}\) + 2x + k 
D
x3 - 2x + k 
Explanation.
Share Answer \(\int\) \(\frac{2x^3 + 2x}{x}\) = \(\int\) \(\frac{2x^3}{x}\) + \(\frac{2x}{x}\) = \(\int\) (2x2 + 2) dx

\(\frac{2x^2+1}{2 + 1}\) + 2x + k

= \(\frac{2x^3}{3}\)+ 2x + k

Correct Option:
C
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Question 3
A

2( \(\frac{1}{3}\)X + 6 )

 
B

\(\frac{2}{3}\) ( \(\frac{1}{3}\)X + 6)

 
C

\(\frac{2}{3}\) ( \(\frac{1}{3}\)X + 6)2

 
D

\(\frac{1}{3}\) ( \(\frac{1}{3}\)X + 6)2

 
Explanation.
Share Answer

Y = ( \(\frac{1}{3}\)X + 6)2

\(\frac{dy}{dx}\) = 2( \(\frac{1}{3}\)X + 6) \(\frac{1}{3}\)

= \(\frac{2}{3}\) ( \(\frac{1}{3}\)X + 6)


Correct Option:
B
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Question 4
A
45 
B
10 
C
35 
D
30 
Explanation.
Share Answer 80 - x + x + 60 - x + 20 = 150
160 - x = 150
x = 160 - 150 = 10

Correct Option:
B
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Question 5
A
B
\(\frac{3}{2}\) 
C
\(\frac{2}{3}\) 
D
Explanation.
Share Answer T2 = \(\frac{8}{9}\), T6 = 4\(\frac{1}{2}\)
ar = \(\frac{8}{9}\)
ar5 = \(\frac{9}{2}\)

\(\frac{ar}{ar^5}\) = \(\frac{8}{9}\) x \(\frac{2}{9}\)

\(\frac{1}{r^4}\) = \(\frac{16}{81}\)

r = \(\sqrt[4]{18/16}\) = \(\frac{3}{2}\)

Correct Option:
B
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Question 8
A

82o

 
B

36o

 
C

72o

 
D

118o

 
Explanation.
Share Answer < MPT = 180o - 118o = 62o

< PML = 62o ( Alternative angle)

y + 2y + 10o + 62o = 180o (Angles on a straight line)

3y = 180 - 72
\(\frac{3y}{3}\) = \(\frac{108}{3}\)
y = 36o

< PMT = 2y + 10 = 2(36) + 10 = 82o

Correct Option:
A
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