Mathematics (2017) | Study Mode

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Question 11
A

3\(^{2n}\)

B

9

C

3n

D

3 \(^{n + 1}\)

Explanation
3\(^{n + 1}\) \(\times\) 27\(\frac{n + 1}{81^n}\)

= 3\(^{n + 1}\) \(\times\) 3 \(\frac{3^{(n + 1)}}{3^{4n}}\)

= 3\(^{n - 1 + 3n + 3 - 4n}\)

= 3\(^{4n - 4n - 1 + 3}\)

= 32

= 9

Correct option: B
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Question 12
A
circle centre P
B
pair of parallel lines each opposite to PQ
C
circle centre Q
D
perpendicular line to PQ
Explanation
The locus of points at a fixed distance from the point P is a circle with the given P at its centre.

The locus of points at a fixed distance from the point Q is a circle with the given point Q at its centre

The locus of points equidistant from two points P and Q i.e line PQ is the perpendicular bisector of the segment determined by the points

Hence, The locus of a point which is equidistant from the line PQ forms a perpendicular line to PQ

Correct option: D
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Question 13
A

{2, 3}

B

{2, 3, 4}

C

{3, 4, 6}

D

{2}

Explanation

Given T = {even numbers from 1 to 12}
= { 2, 4, 6, 8,10, 12}

N = {common factors of 6, 8 and 12}

= {2} Find T n N = {2}


Correct option: D
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Question 14
Mathematics (2017) Q 14 image
A

100o

B

140o

C

120o

D

10o

Explanation
If RST = 60o

RXT = 2 \(\times\) RST

(angle at the centre twice angle at the circumference)

RXT = 2 \(\times\) 60

= 120o

Correct option: C
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Question 15
A

16

B

14

C

12

D

10

Explanation

Range = Highest Number - Lowest Number

Mode is the number with highest occurrence
10, 9, 10, 9, 8, 7, 7, 10, 8, 4, 6,, 9, 10, 9, 7, 10, 6, 5

Range = 10 - 4 = 6


Mode = 10

Sum of range and mode = range + mode = 6 + 10

= 16


Correct option: A
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Question 16
A
\(\frac{1}{2}\)
B
\(\frac{3}{5}\)
C
\(\frac{-1}{5}\)
D
\(\frac{73}{12}\)
Explanation
Sum to infinity

? = arn ? 1

= \(\frac{a}{1}\) ? r

a = \(\frac{1}{4}\)

r = \(\frac{1}{8}\) \(\frac{1}{4}\)

r = \(\frac{1}{s}\) \(\times\) \(\frac{4}{1}\)

= \(\frac{1}{2}\)

S = \(\frac{1 \div 4}{1}\) ? \(\frac{1}{2}\)

= \(\frac{1}{4}\) \(\frac{1}{2}\)

= \(\frac{1}{4}\) \(\times\) \(\frac{2}{1}\)

= \(\frac{1}{2}\)

Correct option: A
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Question 17
Mathematics (2017) Q 17 image
A

6

B

2

C

4

D

5

Explanation

Explanation not provided, please join discuss, your contributions are welcomed


Correct option: B
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Question 18
A
16
B
10
C
18
D
24
Explanation

Explanation not provided, please join discuss, your contributions are welcomed


Correct option: B
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Question 19
A
8
B
6
C
4
D
3
Explanation
2x + x = 180o

3x = 180o

x = 60o (exterior angle of the polygon)

angle = \(\frac{\text{total angle}}{\text{number of sides}}\)

60 = \(\frac{360}{n}\)

n = \(\frac{360}{60}\)

n = 6 sides

Correct option: B
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Question 20
A

23m

B

25m

C

20m

D

22m

Explanation
Capacity = Volume = 3080m3

base diameter = 14m

radius = \(\frac{\text{diameter}}{2}\)

= 7m

Volume of Cylidner = Capacity of cylinder

r2h = 3080

\(\frac{22}{7}\) \(\times\) 7 \(\times\) 7 \(\times\) h = 3080

h = \(\frac{3080}{22 \times 7}\)

h = 20m

Correct option: C

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