# Mathematics 2010 | Study Mode

Question 11
A
26o
B
24o
C
20o
D
23o
##### Explanation
3 + 20 + 88 = 180 (opp s of a cyclic quad are supplementary)
3 + 108 = 180
3 = 180 - 108
3 = 72
= 72/3
= 24o

Question 12
A
10 cm2
B
6 cm2
C
24 cm2
D
8 cm2
##### Explanation
Area of a triangle = 1/2 base x height
= 1/2 x 4 x 5
= 10 cm2

Question 13
A
100/7
B
80/7
C
110/7
D
90/7
##### Explanation
 Area of a sector = x r2 360

= 50/360 x 22/7 x 36/1
= 110/7

Question 14
A
y = - + 6
B
y = - - 6
C
y = + 6
D
y = - 6
##### Explanation
Locus of a point equidistant from two fixed points is the perpendicular bisector of the straight line joining the points Gradients of PQ = (5-3 / 3-1) = 2/2 = 1
Equation of perpendicular bisector
y - y1 = m( - 1
y - 4 = - + 2
y = - + 6

Question 15
A
6 cm
B
7 cm
C
8 cm
D
5 cm
##### Explanation
Area of a triangle = 1/2 ab Sin
123 = 1/2 x 8 x q sin 60
123 = 4 x q x 3/2
123 = 2q3
 q = 123 23

q = 6

Question 16
A
3(2x+1)2
B
6(2x+1)
C
3(2x+1)
D
6(2x+1)2
##### Explanation
y = (2x + 1)3
dy/dx = 3(2x + 1)3-1 x 2
= 3(2x + 1)2 x 2
= 6(2x + 1)2

Question 17
A
cos x + x2 + K
B
cos x 2x + K
C
-cos x + x2 + K
D
-cos x + 2x + K
##### Explanation
(sin + 2)d = (sin + 2)dx
= -cos + 2 + K

Question 18
A
6
B
2
C
7
D
9
##### Explanation
 Marks Number of students 2 3 3 1 4 5 Total 9

Question 19
A
16
B
13
C
20
D
15
##### Explanation
f = 2 + 2 + 8 + 4 + 4
= 20

Question 20
A
3.1
B
3
C
3.2
D
3.3
##### Explanation
 Mark() f f 1 2 2 2 2 4 3 8 24 4 4 16 5 4 20 f = 20 f = 66

 Mean = f f

 = 66 20

= 3.3

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