Mathematics 2008 | Study Mode

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Question 1
A
1110112
B
1101102
C
1010112
D
1010102
Explanation
11012 + 101112 + 1112 = 101011

Correct option: C
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Question 2
A
2
B
3
C
4
D
5
Explanation
125x = 20
1xX2 + 2xX1 + 5xX0 = 20
X2 + 2X + 5 = 20
X2 + 2X - 15 = 0
(X + 5)( X - 3) = 0
X + 5 implies X = -5
X - 3 implies X = 3
But X cannot be negative
X = 3

Correct option: B
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Question 3
A
1/4
B
1/3
C
1/2
D
1
Explanation
\(\frac{\left(\frac{3}{8}\div\frac{1}{2}+\frac{1}{2}\right)}{\left(\frac{1}{8}\times\frac{2}{3}+\frac{1}{3}\right)}\\
=\frac{\left(\frac{3}{8}\times\frac{2}{1}+\frac{1}{2}\right)}{\left(\frac{1}{8}\times\frac{2}{3}+\frac{1}{3}\right)}\\
=\frac{\left(\frac{3}{4}-\frac{1}{3}\right)}{\left(\frac{1}{12}+\frac{1}{3}\right)}\\
=\left(\frac{9-4}{12}\right)\div\left(\frac{1+4}{12}\right)\\
=\left(\frac{5}{12}\right)\div\left(\frac{5}{12}\right)\\
=\frac{5}{12}\times\frac{12}{5}\\
=1\)

Correct option: D
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Question 4
A
123000
B
124000
C
125000
D
126000
Explanation

Explanation not provided, please join discuss, your contributions are welcomed


Correct option: A
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Question 5
A
N3,000
B
N600
C
N300
D
N150
Explanation

\(I = \frac{P \times T \times R}{100}\\
=\frac{7500 \times 8 \times 5}{100}\\
=N3000\)


Correct option: A
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Question 6
A
42%
B
41%
C
40%
D
25%
Explanation
N85 - N60 = N25 increase
percentage increase = \(\frac{25}{60}\times \frac{100}{1}\\=\frac{125}{3}\\=41.67%\\
=42%\)

Correct option: A
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Question 7
A
3/8
B
2/3
C
3/4
D
3/2
Explanation
\(16^{\frac{-1}{2}}\times 4^{\frac{-1}{2}} \times 27^{\frac{1}{3}}\\
=\frac{1}{16^{\frac{1}{2}}}\times \frac{1}{4^{\frac{1}{2}}}\times 27^{\frac{1}{3}}\\
=\frac{1}{\sqrt{16}} \times \frac{1}{\sqrt{4}} \times sqrt[3]{27}\\
=\frac{1}{4} \times \frac{1}{2} \times \frac{3}{1}\\
= \frac{3}{8}\)

Correct option: A
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Question 8
A
4
B
16
C
32
D
64
Explanation
If logx1/264 = 3
(X 1/2)3 = 64
(X 1/2)3 = 4 3
X 1/2 = 4
X = 42
X = 16

Correct option: B
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Question 9
A
(-3, -2)
B
(-2, 3)
C
(3,2)
D
(2,-3)
Explanation
\(\frac{1+\sqrt{2}}{1-\sqrt{2}} \times \frac{1+\sqrt{2}}{1+\sqrt{2}}\\
=\frac{1+(1+\sqrt{2})+\sqrt{2}(1+\sqrt{2})}{1^2 - (\sqrt{2})^2}\\
=\frac{(1+\sqrt{2}+\sqrt{2}+2)}{1-2}\\
=\frac{3+2\sqrt{2}}{-1}\\
=-3-2\sqrt{2}\\
X and Y = -3 and -2\)

Correct option: A
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Question 10
A

{1,3}

B

{5,10}

C

{}

D

{4,6}

Explanation

X = {1,5,10}
Y = {3,4,6}
XY ={}


Correct option: C

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