Mathematics (2015) | Study Mode

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Question 61
A

4

B

5

C

6

D

3

Explanation

Each exterior angle = 180 -120=60

Exterior angle =360/n

60 = 360/n

n =360/6

= 6


Correct option: C
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Question 62
A
N100
B
N20
C
N80
D
N150
Explanation
25% of N80 = 25/100 \(\times\) 80

= N20.00

Correct option: B
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Question 63
A
7.51
B
7.71
C
5.5
D
7.55
Explanation
2.04 x 3.7
=
204
x 37
-----
7548 = 7.548

= 7.55(2dp)

Correct option: D
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Question 64
A

3%

B

2%

C

4%

D

1%

Explanation

Let assume the cost price is 100%

Marked up price + cost price = 20 + 100 = 120%

Discount at 20% = 20/100 \(\times\) 120 % of cost price

Selling price = cost price - gain

= (120 - 24)% of cost price

= 96% of cost price

Loss = (100- 96)% of cost price

= 4% of cost price

- He will wake 4% loss


Correct option: C
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Question 65
A

3(2 + \(\sqrt{5}\))

B

2(3 + \(\sqrt{5}\))

C

5(2 + \(\sqrt{3}\))

D

\(3\sqrt{3}\) + 1

Explanation

5 (2 - \(\sqrt{3}\))

Using conjugate surds

[5 (2 - \(\sqrt{3}\))]\(\times\)(2 + \(\sqrt{3}\)) (2 + \(\sqrt{3}\))]

[5(2+\(\sqrt{3}\))((2- \(\sqrt{3}\)))2]

[5(2 +\(\sqrt{3}\)) (2)2- (\(\sqrt{3}\))2]

[5(2 +\(\sqrt{3}\)) (4- 3)]

= 5(2 + \(\sqrt{3}\))


Correct option: C
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Question 66
A

(a + b)(a - b)

B

(a - 2 + b)

C

(a + 1)(a - 2 + b)

D

(a + b) 2

Explanation

The trinomial = \( a^2 - 4a + 4 \\

a^2 - b^2- 4a + 4 = (a^2 - 4a + 4) - b^2 \\

(a^2 - 2a - 2a + 4) - b^2 \\

[a(a - 2)- 2(a - 2)] - b^2 \\

(a - 2)2 - b^2 \\

(a - 2 + b)(a - 2 - b )\)


Correct option: B
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Question 67
A
\(\frac{2\sqrt{13}}{13}\)
B
\(\frac{3\sqrt{13}}{13}\)
C
\(\frac{4\sqrt{13}}{13}\)
D
\(\frac{6\sqrt{13}}{13}\)
Explanation
tan x = \(\frac{2}{3}\)(given), is illustrated in a right-angled \(\Delta\)

thus m2 = 22 + 32

= 4 + 9 = 13

m = \(\sqrt{13}\)

Hence, 2sin x = 2 x \(\frac{2}{m}\)

2 x\(\frac{2}{\sqrt{13}}\)

= \(\frac{4}{\sqrt{13}}\)

= \(\frac{4}{\sqrt{13}} = \frac{\sqrt{13}}{\sqrt{13}}\)

= \(\frac{4\sqrt{13}}{13}\)

Correct option: C

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