# MATHEMATICS | Study Mode

Question 1
A

2211

B

2121

C

1212

D

1122

Question 2
A

10103

B

11003

C

10003

D

10013

Question 3
A
24
B
16
C
38
D
36
##### Explanation

The sum, S of ratio is S = 5 + 3 + 2 = 10.

But highest share = $$\frac{5}{10} \times T$$, where T is the total number of apples.

Thus, $$40 = \frac{5}{10} \times T$$,

given 40 x 10 = 5T,

$$T = \frac{40 \times 10}{5} = 80$$

Hence the smallest share = $$\frac{2}{10} \times 80$$

= 16 apples

Question 4
A

6.2

B

6.3

C

0.5

D

0.6

##### Explanation

Question 5
A

3 years

B

3$$\frac{1}{2}$$ years

C

1$$\frac{1}{2}$$ years

D

2$$\frac{1}{2}$$ years.

##### Explanation

Using $$S.I =\frac{P \times T \times R}{100}$$

$$600 =\frac{3000 \times T \times 8}{100}$$

$$T =\frac{600 \times 100}{3000 \times 8}$$

$$\frac{20}{8}$$

= 2$$\frac{1}{2}$$ years

Question 6
A

33

B

35

C

3

D

32

##### Explanation

$$\frac{3^{-5n}}{9^{1-n}} \times 27^{n + 1}$$

$$\frac{3^{-5n}}{3^{2(1-n)}} \times 3^{3(n + 1)}$$

$$3^{-5n} \div 3^{2(1-n)} \times 3^{3(n + 1)}$$

$$3^{-5n - 2(1-n) + 3(n + 1)}$$

$$3^{-5n - 2 + 2n + 3n + 3}$$

$$3^{-5n + 5n + 3 - 2}$$

$$3^{1}$$

= 3

Question 7
A

0.9021

B

1.8063

C

0.2007

D

0.3011

Question 8
A

1/5

B

1/9

C

9

D

5

Question 9
A

.

B

.

C

.

D

.

##### Explanation

Question 10
A

{3,5,11,13,17,19}

B

{3,5,7,9,11,13,15,17,19}

C

{2,3,5,7,11,13,17,19}

D

{3,5,7,11,17,19}