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caesium has a work function of 3 x 10-19J. the maximum energy of liberated...

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Question 33

caesium has a work function of 3 x 10^-19J. the maximum energy of liberated electrons when it is illuminated by light of frequency 6.7 x 10¹⁴

HZ is?



[h = 6.6 x 1010^-34Js]

A

1.42 x 10^-19J

B

3.00 x 10^-19J

C

4.42 x 1010^-19J

D

7.42 x 10^-19J

Explanation

Share Answer Max kinetic energy = Energy of incident electron - work function. EK = hf - w
= 6.6 x 10^-34 x 6.7 x 10¹⁴ - 3 x 10^-19
= 4.422 x 10^-19 - 3 x 10^-19
= 1.422 x 10^-19J

Correct option: A

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