Physics 2008 Discuss

A force F required to keep a 5 kg mass moving round a cycle of radius 3.5...

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Question 39
A
4.0 ms-1
B
6.6 ms-1
C
12.1 ms-1
D
21.0 ms-1
Explanation
The force which is centripetal
F = MV2_R
=5 x 723.5
= 70
V = (Fr) and if F is tripped, then
V = (3Fr)/m
= (3x70x3.5)/5
= 12.1ms-1

Correct option: C

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