# Simplify : $$\frac{3^{-5n}}{9^{1-n}} \times 27^{n + 1}$$

Question 6
A

33

B

35

C

3

D

32

##### Explanation

$$\frac{3^{-5n}}{9^{1-n}} \times 27^{n + 1}$$

$$\frac{3^{-5n}}{3^{2(1-n)}} \times 3^{3(n + 1)}$$

$$3^{-5n} \div 3^{2(1-n)} \times 3^{3(n + 1)}$$

$$3^{-5n - 2(1-n) + 3(n + 1)}$$

$$3^{-5n - 2 + 2n + 3n + 3}$$

$$3^{-5n + 5n + 3 - 2}$$

$$3^{1}$$

= 3

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1 Comment(s)

Philip Michael said on February 9, 2021 12:24pm
After solving this, i had 3^4n-1 using the law of indices
how come is the answer 3^2
QUIZZERWEB replied on February 12, 2021 06:44pm
We are very sorry about that, the question has been updated